pairs of vertices interpreted as individual line segments
pairs of vertices interpreted as individual line segments
same as above, with a segment added between last and first vertices
same as above, with a segment added between last and first vertices
series of connected line segments
series of connected line segments
individual points
individual points
boundary of a simple, convex polygon
boundary of a simple, convex polygon
quadruples of vertices interpreted as four-sided polygons
quadruples of vertices interpreted as four-sided polygons
linked strip of quadrilaterals
linked strip of quadrilaterals
triples of vertices interpreted as triangles
triples of vertices interpreted as triangles
linked fan of triangles
linked fan of triangles
linked strip of triangles
linked strip of triangles
This method is used to compare the receiver object (this
)
with the argument object (arg0
) for equivalence
This method is used to compare the receiver object (this
)
with the argument object (arg0
) for equivalence.
The default implementations of this method is an equivalence relation:
x
of type Any
,
x.equals(x)
should return true
.x
and y
of type
Any
, x.equals(y)
should return true
if and only
if y.equals(x)
returns true
.x
, y
, and z
of type AnyRef
if x.equals(y)
returns true
and
y.equals(z)
returns
true
, then x.equals(z)
should return true
.
If you override this method, you should verify that
your implementation remains an equivalence relation.
Additionally, when overriding this method it is often necessary to
override hashCode
to ensure that objects that are
"equal" (o1.equals(o2)
returns true
)
hash to the same Int
(o1.hashCode.equals(o2.hashCode)
).
the object to compare against this object for equality.
true
if the receiver object is equivalent to the argument; false
otherwise.
Returns a hash code value for the object
Returns a hash code value for the object.
The default hashing algorithm is platform dependent.
Note that it is allowed for two objects to have identical hash
codes (o1.hashCode.equals(o2.hashCode)
) yet not be
equal (o1.equals(o2)
returns false
). A
degenerate implementation could always return 0
.
However, it is required that if two objects are equal
(o1.equals(o2)
returns true
) that they
have identical hash codes
(o1.hashCode.equals(o2.hashCode)
). Therefore, when
overriding this method, be sure to verify that the behavior is
consistent with the equals
method.
Returns a string representation of the object
Returns a string representation of the object.
The default representation is platform dependent.